If (p wedge sim q) wedge (p wedge r) to sim p | vedclass

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(B) conditional statement $A 	o B$ is false if and only if $A$ is true and $B$ is false.Here,$A = (p \wedge \sim q) \wedge (p \wedge r)$ and $B = \si

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$T, F, T$

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(B) conditional statement $A 	o B$ is false if and only if $A$ is true and $B$ is false.Here,$A = (p \wedge \sim q) \wedge (p \wedge r)$ and $B = \sim p \vee q$.For $A 	o B$ to be false,we must have $A = T$ and $B = F$.$1$. Since $A = (p \wedge \sim q) \wedge (p \wedge r) = T$,all components must be true: $p = T$,$\sim q = T$ (so $q = F$),and $r = T$.$2$. Now,check if $B = \sim p \vee q$ is false with these values: $\sim T \vee F = F \vee F = F$.Since $B = F$ holds,the values $p = T, q = F, r = T$ satisfy the condition.Therefore,the truth values are $p = T, q = F, r = T$.

If $(p \wedge \sim q) \wedge (p \wedge r) \to \sim p \vee q$ is false,then the truth values of $p, q$ and $r$ are respectively

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